vvv XC A Capacitor reacts to an increase in voltage across the capacitance by presenting itself as short circuit to the change in the voltage. An increase in applied voltage is countered by the capacitor appearing as low ohms, thereby absorbing enough source current to effectively lower the source voltage to oppose that increase in voltage. The more rapid the change in voltage, the more the opposition by the Capacitance to those changes. The Capacitance will also oppose decreases in voltage, by returning current into the circuit, which aids the source voltage, and thereby tries to maintain the source voltage before the decrease. Because events per second are considered cyclic, and cyclic indicates circles, the formula for Capacitive Reactance has two times pi as a constant, with the rapidity as frequency in Hz. The resulting Capacitive Reactance is also dependant on the amount or value of Capacitance in Farads. The actual formula then is simply the 2 pi, times the frequency, times the value of Capacitance. This resulting value is inverted, as a reciprocal, giving a value of Capacitive Reactance in Ohms. Simply stated, because of the reciprocal relationship, the resulting value of Capacitive Reactance in Ohms, decreases as the frequency increases. + !